Yes I have. They all played Sam twice. In this scenario, UCA and SFA would be 1-1 and HBU 0-2. However, the tiebreaker stipulates that for the tie to be split, one team has to have an advantage. So, even though SFA and UCA did better, it goes to the next common team.
There is not another team that they all played twice, so it goes to the "Three way tiebreaker subsection (c)." That says:
(c) If three (3) or more teams remain tied for a position, regardless of the number of games played against the other tied teams, any won-loss advantage in the combined pool of tied teams shall be used as a seeding tie-breaker. This shall continue through the order of final standings if necessary.
We are 2-1 against HBU and UCA.
HBU is 1-1, UCA is 1-2.
We have the advantage so we advance to the #7 seed. Then it goes to a two way tiebreaker which UCA wins by beating Sam (common opponent) once. UCA #8.
There is not another team that they all played twice, so it goes to the "Three way tiebreaker subsection (c)." That says:
(c) If three (3) or more teams remain tied for a position, regardless of the number of games played against the other tied teams, any won-loss advantage in the combined pool of tied teams shall be used as a seeding tie-breaker. This shall continue through the order of final standings if necessary.
We are 2-1 against HBU and UCA.
HBU is 1-1, UCA is 1-2.
We have the advantage so we advance to the #7 seed. Then it goes to a two way tiebreaker which UCA wins by beating Sam (common opponent) once. UCA #8.